25x^2+35x-30=0

Solution for 25x^2+35x-30=0 equation:

25x^2+35x-30=0

a = 25; b = 35; c = -30;
Δ = b2-4ac
Δ = 352-4·25·(-30)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-65}{2*25}=\frac{-100}{50}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+65}{2*25}=\frac{30}{50}
=3/5
$